18x^2-34x+8=0

Solution for 18x^2-34x+8=0 equation:

18x^2-34x+8=0

a = 18; b = -34; c = +8;
Δ = b2-4ac
Δ = -342-4·18·8
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{145}}{2*18}=\frac{34-2\sqrt{145}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{145}}{2*18}=\frac{34+2\sqrt{145}}{36}
$